This section shows you how to factorise and includes examples, sample questions and videos Brackets should be expanded in the following ways For an expression of the form a(b c), the expanded version is ab ac, ie, multiply the term outside the bracket by everything inside the bracket (eg 2x(x 3) = 2x²Y = 5 xy (b) 63m 3 n, 54mn 4 63m 3 n = 3 ×Ans Given 25m 2 30m9 Since, 25m 2 , 30m and 9 can be substituted by (5m) 2, 2×5m×3 and 3 2 respectively we get, = (5m) 2 2×5m×3 3 2 Therefore, by using the identity (xy) 2 = x 2 2xyy 2 25m 2 30m9 = (5m3) 2
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Factorise 3(x+y)^2-5(x+y)+2-9/19/Explore numerous MCQ Questions of Factorisation Class 8 with answers provided with detailed solutions by looking below Question 1 Factorise 4y 2 −12y 9 (a) (7y− 5) 2 (b) (5y− 3) 2 (c) (2y− 5) 2 (d) (2y− 3) 2 AnswerEx 25 Class 9 Maths Question 5 Factorise (i) 4x 2 9y 2 I62 2 12xy – 24yz 16xz (ii) 2x 2 y 2 2 – 2 xy 4 yz – 8×2 Solution (i) 4x 2 9y 2 16z 2 12xy24yz16xz = (2x) 2 (3y) 2 (4z) 2 2 (2x) (3y) 2 (3y) (4z) 2 (4z) (2x) = (2x 3y – 4z) 2 (ii) 2x 2 y 2 8z 2 – 2


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3/3/Factorize each of the following algebraic expressions 4(x y) (3a – b) 6(x y) (2b – 3a) Welcome to Sarthaks eConnect A unique platform where students can interact with teachers/experts/students to get solutions to their queries1/30/18Which of the following is a factor of (x y) 3 – (x 3 y 3)?SolutionShow Solution (x 2 y 2 z 2) 2 4x 2 y 2 = (x 2 y 2 z 2) 2 (2xy) 2 = (x 2 y 2 z 2 2xy) (x 2 y 2 z 2 2xy) = (x 2 y 2 2xy) z 2 (x 2 y 2 2xy) z 2
11/4/17Solve mxny=m2 n2 ;5 is a factorization of the integer 15, and (x – 2)(x 2) is a factorization of the polynomial x 2 – 4View Full Answer 4 (ba) 2
N 54mn 4 = 2 ×Xy = 2m In the centre of a rectangular lawn of dimensions 50m x 40m, a rectangular pond has to be constructed, so that the area of the grass surrounding the pond would be 1184 m2see figureFactorise the Following by Taking Out the Common Factors 36(X Y)3 54(X Y)2 CISCE ICSE Class 9 Question Papers 10 Textbook Solutions Important Solutions 5 Question Bank Solutions Concept Notes &



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Learn to factorise an expression of the form x^4 x^2y^2 y^4 This is solved by adding and subtracting x^2y^2 to the given expression and reducing it to tN Common factors are 3 ×Download the PDF Question Papers Free for off line practice and view the Solutions online Currently only available for Class 10 Class 12



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Follow Report Log in to add a comment9/6/16You can observe that $xy = (xy)$ So both $x^2y^2$ and $xy$ have $xy$ as a factor You can use these info to get below factorization $$ x^2 y^2 x y = (xy)(xy)(xy) = (xy1)(xy(a) x 2 y 2 2xy (b) x 2 y 2 – xy (c (x y) 2 (x 2 xy y 2) = (x y)(x 2 y 2 2xy x 2 x y y 2) using identity, (a b)2 = a 2 b 2 2 ab) = (x y) (3xy) Hence, one of the factor of given polynomial is 3xy factorise the polynomial x3 x2 4x 4



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Y 30xy 2 = 2 ×Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor, former Associate Professor (Honorary) Pure Math at University of New South Wales ()



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Here are some examples illustrating how to ask about factoring factor quadratic x^27x12 expand polynomial (x3) (x^35x2) GCD of x^42x^39x^246x16 with x^48x^325x^246x16 quotient of x^38x^217x6 with x3 remainder of x^32x^25x7 divided by x3 roots of x^23x2 View more examples »Consider x 2 y 2 x y − 2 2 x y as a polynomial over variable x Find one factor of the form x^ {k}m, where x^ {k} divides the monomial with the highest power x^ {2} and m divides the constant factor y^ {2}y2 One such factor is xy1 Factor the polynomial by dividing it by this factorFactorize the following i) x 2x12 ii) x 27x12 iii) 2x 32x 260x iv) (xy) 2(xy) 2 v) 9x 2 y 216z 2 vi) 16x 4625y 4 vii) x 4(yz) 4 viii) x 211x18 ix) x 2 17x18 x) x 216x36



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